0.2X^2+600x-600=0

Solution for 0.2X^2+600x-600=0 equation:

0.2X^2+600X-600=0

a = 0.2; b = 600; c = -600;
Δ = b2-4ac
Δ = 6002-4·0.2·(-600)
Δ = 360480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{360480}=\sqrt{16*22530}=\sqrt{16}*\sqrt{22530}=4\sqrt{22530}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-4\sqrt{22530}}{2*0.2}=\frac{-600-4\sqrt{22530}}{0.4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+4\sqrt{22530}}{2*0.2}=\frac{-600+4\sqrt{22530}}{0.4}
$